## Chemistry: The Molecular Science (5th Edition)

For a sample of seawater with pH = 8.30: $[H_3O^+] = 5.0 \times 10^{- 9}M$
$[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 8.30}$ $[H_3O^+] = 5.0 \times 10^{- 9}M$