#### Answer

For a sample of seawater with pH = 8.30:
$[H_3O^+] = 5.0 \times 10^{- 9}M$

#### Work Step by Step

$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 8.30}$
$[H_3O^+] = 5.0 \times 10^{- 9}M$

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Cengage Learning

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1285199049

ISBN 13:
978-1-28519-904-7

For a sample of seawater with pH = 8.30:
$[H_3O^+] = 5.0 \times 10^{- 9}M$

$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 8.30}$
$[H_3O^+] = 5.0 \times 10^{- 9}M$

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