Answer
For a sample of seawater with pH = 8.30:
$[H_3O^+] = 5.0 \times 10^{- 9}M$
Work Step by Step
$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 8.30}$
$[H_3O^+] = 5.0 \times 10^{- 9}M$
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