Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652b: 29

Answer

The $pOH$ value of this solution is 12.505.

Work Step by Step

- Hydronium concentration $(H_3O^+)$ = 0.032M; 1. Calculate the pH value. $pH = -log[H_3O^+]$ $pH = -log( 0.032)$ $pH = 1.495$ 2. Use the pH value to calculate the pOH. $pOH + pH = 14$ $pOH = 14 - pH = 14 - 1.495$ $pOH = 12.505$
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