# Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652b: 34a

$pH = 6.215$ $[OH^-] = 1.639 \times 10^{- 8}M$ This solution is acidic.

#### Work Step by Step

$[H_3O^+] * [OH^-] = Kw = 10^{-14}$ $6.1 \times 10^{- 7} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 6.1 \times 10^{- 7}}$ $[OH^-] = 1.639 \times 10^{- 8}M$ $pH = -log[H_3O^+]$ $pH = -log( 6.1 \times 10^{- 7})$ $pH = 6.215$ $[H_3O^+] > [OH^-]$: Acidic solution Assuming $25 ^{\circ}C$: pH < 7 : Acidic solution.

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