Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652b: 30

Answer

The pH of the solution is 11.38, and its pOH is 2.62

Work Step by Step

$pOH = -log[OH^-]$ $pOH = -log( 2.4 \times 10^{- 3})$ $pOH = 2.62$ $pH + pOH = 14$ $pH + 2.62 = 14$ $pH = 11.38$
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