#### Answer

pH = 12.40
pOH = 1.60

#### Work Step by Step

- NaOH is a strong base, therefore: $[OH^-] = [NaOH] = 0.025M$
1. Calculate the hydronium concentration:
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$
$ 2.5 \times 10^{- 2} * [H_3O^+] = 10^{-14}$
$[H_3O^+] = \frac{10^{-14}}{ 2.5 \times 10^{- 2}}$
$[H_3O^+] = 4 \times 10^{- 13}$
2. Calculate the pH Value
$pH = -log[H_3O^+]$
$pH = -log( 4 \times 10^{- 13})$
$pH = 12.40$
3. Use this value to calculate the pOH:
$pH + pOH = 14$
$12.40 + pOH = 14$
$pOH = 14 - 12.40 = 1.60$