Answer
Reactants:
Acid: $NH_3$
Base: $N{H_2}^-$
Products:
Conjugate base: $N{H_2}$
Conjugate acid: $NH_3$
Work Step by Step
Reactants: Left side of the reaction.
Products: Right side.
1. Identify the acid and the base of the reactants:
- $NH_3$ is turning into $N{H_2}^-$; therefore, it is donating one proton, so it is the acid.
- $N{H_2}^-$ is turning into $NH_3$; therefore, it is receiving one proton, so it is the base.
2. Identify the conjugate acid and base:
- The conjugate base is the result of an acid losing a $H^+$. Since $NH_3$ is the acid, $N{H_2}^-$ is the conjugate base.
- The conjugate acid is the result of a base gaining a $H^+$. Since $N{H_2}^-$ is the base, $NH_3$ is the conjugate acid.
