# Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652a: 13f

Hydrogen sulfite $(HS{O_3}^-)$ is the conjugate partner of $S{O_3}^{2-}$.

#### Work Step by Step

1. Identify if the substance is an acid or a base (or both): - $S{O_3}^{2-}$ is a base. 2. Since $S{O_3}^{2-}$ is a base, add one proton to it: - Add one hydrogen and sum one to the charge: $S{O_3}^{2-} -- \gt HS{O_3}^-$ - This is the conjugate acid of $S{O_3}^{2-}$. 3. Name it: $S{O_3}^{2-}$: Sulfite ion. $HS{O_3}^- = H^+ + S{O_3}^{2-}$; Therefore: $HS{O_3}^-$ = Hydrogen sulfite.

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