Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Questions for Review and Thought - Topical Questions - Page 652a: 13e


Sulfate ion ($S{O_4}^{2-}$) and Sulfuric acid ($H_2SO_4$) are the conjugate partners of $HS{O_4}^-$.

Work Step by Step

1. Identify if the substance is an acid or a base (or both): - $HS{O_4}^-$ can act as an acid or as a base. When it acts as a base: 2. Add one proton to it: - Add one hydrogen and sum one to the charge: $H{SO_4}^- -- \gt H_2SO_4$ - This is the conjugate acid of $HS{O_4}^-$. 3. Name it: Sulfur ("S") has 2 oxyacids: $H_2SO_3$ and $H_2SO_4$. So, since $H_2SO_4$ is the one where "S" has the highest oxydation number, it receives an "ic" on the name: $H_2SO_4$ = "Sulfuric acid." When it acts as an acid: 4. Remove one proton from it: - Remove one hydrogen and subtract one from the charge: $HS{O_4}^- -- \gt S{O_4}^{2-}$ - This is the conjugate base of $HS{O_4}^-$. 5. Name it: $H_2SO_4$ = Sulfuric acid. "ic" acids $->$ "ate" ions. $S{O_4}^{2-}$ = Sulfate ion.
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