Answer
$NH_3$ and $N{H_4}^+$ are a conjugate acid-base pair.
Work Step by Step
- Fast method:
A conjugate acid-base pair has exactly one $H^+$ as a difference. So, this is a valid pair.
- Other method:
1. Identify the base:
- $NH_3$
2. Add a $H^+$ to it:
- $N{H_4}^+$
Compare it to the other substance:
$N{H_4}^+ = N{H_4}^+$
- So, this is a conjugate acid-base pair.
