Reactants: - Acid: $H_2O$ - Base: $HS^-$ Products: - Conjugate base: $OH^-$ - Conjugate acid: $H_2S$
Work Step by Step
Reactants: Left side of the reaction. Products: Right side. 1. Identify the acid and the base of the reactants: - $H_2O$ is turning into $OH^-$; therefore, it is donating one proton, so it is the acid. - $HS^-$ is turning into $H_2S$; therefore, it is receiving one proton, so it is the base. 2. Identify the conjugate acid and base: - The conjugate base is the result of an acid losing a $H^+$. Since $H_2O$ is the acid, $OH^-$ is the conjugate base. - The conjugate acid is the result of a base gaining a $H^+$. Since $HS^-$ is the base, $H_2S$ is the conjugate acid.