## Chemistry: Molecular Approach (4th Edition)

$$1.7 \space L$$
1. Using the equation: $M_1V_1 = M_2V_2$ $$\frac{M_1V_1}{M_2} = V_2$$ $$V_2 = \frac{( 10.0 \space M)( 25 \space mL )}{ 0.150 \space M} = 1.7 \times 10^{3} \space mL = 1.7 \space L$$