Chemistry: Molecular Approach (4th Edition)

1. Use the molarity as a conversion factor: a. $$0.45 \space mol \times \frac{1 \space L}{0.200 \space mol} = 2.3 \space L$$ b. $$1.22 \space mol \times \frac{1 \space L}{0.200 \space mol} = 6.10 \space L$$ c. $$1.2 \times 10^{-2} \space mol \times \frac{1 \space L}{0.200 \space mol} = 0.060 \space L$$