Answer
The molarity of the diluted solution is 0.27 M $glucose$.
Work Step by Step
1. Using the equation: $M_1V_1 = M_2V_2$
$$\frac{M_1V_1}{V_2} = M_2$$
$$M_2 = \frac{( 1.1 \space M)( 123 \space mL )}{ 500.0 \space mL } = 0.27 \space M$$
Chemistry: Molecular Approach (4th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
0134112830
ISBN 13:
978-0-13411-283-1
Chapter 4 - Exercises - Page 188: 61
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