## Chemistry: Molecular Approach (4th Edition)

The molarity of the diluted solution is 0.27 M $glucose$.
1. Using the equation: $M_1V_1 = M_2V_2$ $$\frac{M_1V_1}{V_2} = M_2$$ $$M_2 = \frac{( 1.1 \space M)( 123 \space mL )}{ 500.0 \space mL } = 0.27 \space M$$