Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 4 - Exercises - Page 188: 56


a. $ 0.200 \space M \space Cl^- $ b. $0.300 \space M \space Cl^- $ c. $0.300 \space M \space Cl^- $

Work Step by Step

1. Determine the amount of $Cl^-$ ions in each compound: a. 1 b. 2 c. 3 2. Use them as conversion factors: a. $$0.200 \space M \space NaCl \times \frac{1 \space mol \space Cl^-}{1 \space mol \space NaCl} = 0.200 \space M \space Cl^- $$ b. $$0.150 \space M \space SrCl_2 \times \frac{2 \space mol \space Cl^-}{1 \space mol \space SrCl_2} = 0.300 \space M \space Cl^- $$ c. $$0.100 \space M \space AlCl_3 \times \frac{3 \space mol \space Cl^-}{1 \space mol \space AlCl_3} = 0.300 \space M \space Cl^- $$
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