Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 39

Answer

See answer below.

Work Step by Step

Number of moles of sodium carbonate: $6.73\ g\div 105.988\ g/mol=0.0635\ mol$ Concentration: $0.0635\ mol/0.250\ L=0.254\ M$ For the ions, from stoichiometry: $Na^+$: $0.508\ M$ $CO_3^{2-}$: $0.254\ M$
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