Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179d: 37

Answer

$Ni(CO)_4$

Work Step by Step

Number of moles of $CO_2$: $0.100\ g\div 44.001\ g/mol=0.00227\ mol$ $0.00227\ mol$ of CO Number of moles of $NiO$: $0.0426\ g\div 74.693\ g/mol=0.00057\ mol$ $0.00057\ mol$ of Ni Ratio: $4.00$ Empirical formula: $Ni(CO)_4$
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