Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179d: 41


$493.8\ mg$

Work Step by Step

Number of moles: $0.0125\ M\times 250.\ mL= 3.125\ mmol$ Mass: $3.125\ mmol\times 158.03\ mg/mmol=493.8\ mg$
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