Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 36

Answer

See answer below.

Work Step by Step

Number of moles of $CO_2$: $0.3718\ g\div 44.001\ g/mol=0.00845\ mol$ From stoichiometry: $0.00845\ mol$ of C, $0.00845\ mol\times12.011\ g/mol=0.1015\ g$ Number of moles of $H_2O$: $0.1522\ g\div 18.015\ g/mol=0.00845\ mol$ From stoichiometry: $0.0169\ mol$ of H, $0.0169\ mol\times1.008\ g/mol=0.0170\ g$ Number of moles of O : $(0.1523-0.1015-0.0170)\ g\div 15.9994\ g/mol=0.00211\ mol$ H/O Ratio: $0.0169/0.00211=8.00$ C/O Ratio: $0.00845/0.00211=4.00$ Empirical formula: $C_4H_8O$ Molar mass of the empirical formula: $72.11\ g/mol$ Ratio of the molar masses: $72.1/72.11=1.00$ Molecular formula: $C_4H_8O$
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