## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179d: 35

#### Answer

Empirical formula: $CH_3O$ Molecular formula: $C_2H_6O_2$

#### Work Step by Step

Number of moles of $CO_2$: $0.1356\ g\div 44.001\ g/mol=0.00308\ mol$ $0.00308\ mol$ of C, $0.0370\ g$ Number of moles of $H_2O$: $0.0833\ g\div 18.015\ g/mol=0.00462\ mol$ $0.00925\ mol$ of H, $0.00932\ g$ Number of moles of O : $(0.0956-0.0370-0.0093)\ g\div 15.9994\ g/mol=0.00308\ mol$ H/C Ratio: $3.00$ O/C Ratio: $1.00$ Empirical formula: $CH_3O$ Molar mass of the empirical formula: $31.03\ g/mol$ $62.1/31.03=2.00$ Molecular formula: $C_2H_6O_2$

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