Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 30

Answer

$8.80\%$

Work Step by Step

Number of moles of the oxide: $127\ mg\div 101.961\ mg/mmol=1.255\ mmol$ From stoichiometry: $1.255\ mmol\times 2_{Al(OH)_3}/1_{Al_2O_3}\times 1_{Al}/1_{Al(OH)_3}=2.491\ mmol$ of Al Mass fraction: $2.491\ mmol\times26.982\ mg/mmol=67.2\ mg$ $67.2/764\times100\%=8.80\%$
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