Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179c: 25



Work Step by Step

Number of moles of water removed: $(1.245\ g - 0.832\ g)/18.015\ g/mol=0.0229\ mol$ Number of moles of the hydrated salt: $0.0229\ mol/5=0.0046\ mol$ Mass fraction of the hydrated salt: $0.0046\ mol\times 249.685\ g/mol=1.145\ g$ $1.145/1.245\times100\%=91.95\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.