Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179c: 28



Work Step by Step

Number of moles of $CO_2$: $0.196\ g/44.001\ g/mol=0.00445\ mol$ From stoichiometry, the number of moles of sodium bicarbonate: $0.00445\ mol\times 2_{Na_HCO_3}/1_{Na_3CO_3}=0.00891\ mol$ $0.00891\ mol\times 84.007\ g/mol=0.7484\ g$ Mass fraction: $0.7484\ g/1.7184\ g=43.55\%$
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