## Chemistry and Chemical Reactivity (9th Edition)

$43.55\%$
Number of moles of $CO_2$: $0.196\ g/44.001\ g/mol=0.00445\ mol$ From stoichiometry, the number of moles of sodium bicarbonate: $0.00445\ mol\times 2_{Na_HCO_3}/1_{Na_3CO_3}=0.00891\ mol$ $0.00891\ mol\times 84.007\ g/mol=0.7484\ g$ Mass fraction: $0.7484\ g/1.7184\ g=43.55\%$