Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179c: 24


$269\ g$

Work Step by Step

Mass: $0.791\ g/mL\times 1000\ mL=791\ g$ Percent yield: $74\%=791\ g/T.Y. \times 100\%$ $T.Y.= 1068.92\ g$ Number of moles of methanol: $1068.92\ g/16.04\ g/mol=66.64\ mol$ From stoichiometry: $66.64\ mol\times 2_{H_2}/1_{CH_4}\times 2.016\ g/mol=269\ g$
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