Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 22

Answer

Theoretical yield: $9.37\ g$ Percent yield: $92.27\%$

Work Step by Step

Number of moles of $CH_3SH$: $10.0\ g\div 48.11\ g/mol=0.208\ mol$ Theoretical yield: $0.208\ mol \times 1_{CH_3COSCH_3}/2_{CH_3SH}\times 90.14\ g/mol=9.37\ g$ Percent yield: $8.65/9.37\times100\%=92.37\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.