Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95i: 143


$5.52\times10^{-4}\ mol$ $346.26\ mg$

Work Step by Step

Molar mass: $21\times12.011+15\times1.008+208.980\times3+15.999\times12=1086.28\ g/mol$ Mass fraction of Bi: $208.980\times3/1086.28\times100\%=57.71\%$ In two tablets: $600.\times10^{-3}\ g\div1086.28\ g/mol=5.52\times10^{-4}\ mol$ Mass of bismuth: $600.\ mg\times57.71/100=346.26\ mg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.