# Chapter 2 Atoms, Molecules, and Ions - Study Questions: 143

$5.52\times10^{-4}\ mol$ $346.26\ mg$

#### Work Step by Step

Molar mass: $21\times12.011+15\times1.008+208.980\times3+15.999\times12=1086.28\ g/mol$ Mass fraction of Bi: $208.980\times3/1086.28\times100\%=57.71\%$ In two tablets: $600.\times10^{-3}\ g\div1086.28\ g/mol=5.52\times10^{-4}\ mol$ Mass of bismuth: $600.\ mg\times57.71/100=346.26\ mg$

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