Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95i: 130


Empirical formula: $C_2H_{6}As$ Molecular formula: $C_4H_{12}As_2$

Work Step by Step

Atomic weights (g/mol): $C: 12.011, \ H: 1.008,\ As: 74.921$ In 100 g : C: $22.88\ g \div 12.011 \ g/mol=1.90\ mol$ H: $5.76\ g\div1.008\ g/mol=5.71\ mol$ As: $71.36\ g\div74.921\ g/mol=0.952\ mol$ Dividing all these number of moles by the smallest value (0.952) leads to the empirical formula: $C_2H_6As$ Molar mass of the empirical formula: $104.99\ g/mol$ Molar mass of the compound: $210\ g/mol$ Ratio of the two: 2.00 Molecular formula: $C_4H_{12}As_2$
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