## Chemistry and Chemical Reactivity (9th Edition)

$n=2189$
Molar mass as a function of n: $79.904\times3+12.011\times6+1.008\times3+n\times(12.011\times8+1.008\times8)=$ $314.802+n\times104.152\ g/mol$ Mass fraction of Br: $0.105/100=79.904\times3\div(314.802+n\times104.152)$ Solving for n: $n=2189$