Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95i: 147

Answer

$n=2189$

Work Step by Step

Molar mass as a function of n: $79.904\times3+12.011\times6+1.008\times3+n\times(12.011\times8+1.008\times8)=$ $314.802+n\times104.152\ g/mol$ Mass fraction of Br: $0.105/100=79.904\times3\div(314.802+n\times104.152)$ Solving for n: $n=2189$
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