Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions: 141

Answer

D

Work Step by Step

Barium is from group 2, hence : $Ba^{2+}$ is its cation, so the anion molybdate is $MoO_4^{2-}$ Sodium molybdate is then $Na_2MoO_4$.
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