Chemistry and Chemical Reactivity (9th Edition)

a) Pressure difference between the bottom and the top of the tree: $10.0\ m_{H_2O}\times 1000\ mmH_2O/m_{H_2O}\times (1\ mmHg/13.6\ mmH_2O)\times 1\ atm/760\ mmHg=0.967\ atm$ The minimum osmotic pressure would need to be greater than this pressure difference for the solute to rise: $\Pi=cRT\rightarrow c=0.967\ atm\div(0.082\ atm/M.K\times 293\ K)=0.04\ M$ b) Mass of 1 L of the solution: $1000\ mL\times 1.0\ g/mL=1000\ g$ Mass of sucrose: $0.04\ mol/L\times 1\ L\times 342.30\ g/mol=13.78\ g$ Weight percent: $13.78/1000\times 100\%=1.38\%$