Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505d: 67

Answer

$406.35\ g/mol$

Work Step by Step

B.p. elevation: $61.93-61.70=0.23^{\circ}C$ Molality: $\Delta T_b=K_bm\rightarrow 0.23^{\circ}C=3.63^{\circ}C\times m\rightarrow m=0.063\ mol/kg$ Number of moles: $0.063\ mol/kg\times (25.0/1000)kg=0.0016\ mol$ Molar mass : $0.640\ g\div 0.0016\ mol=406.35\ g/mol$
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