Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505d: 66



Work Step by Step

B.p. elevation: $61.82-61.70=0.12^{\circ}C$ Molality: $\Delta T_b=K_b,m\rightarrow m=0.12^{\circ}C\div3.63^{\circ}C/m=0.033\ mol/kg$ Number of mols: $0.033\ mol/kg\times(25/1000)kg=8.26\times10^{-4}\ mol$ Molar mass: $0.135\ g\div 8.26\times10^{-4}\ mol=163.35\ g/mol$ Molar mass of empirical formula: $82.10\ g/mol$ Ratio of the molar masses: $163.35\div 82.10=1.99\approx 2$ Molecular formula: $C_{10}H_{12}O_2$
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