Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403b: 31


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Work Step by Step

Number of moles of iron: $2.2\ g/div 55.845\ g/mol=0.0394\ mol$ From stoichiometry: $0.0394\ mol$ of $H_2$ From ideal gas law: $P.V=n.R.T$ $P=0.082057\ L.atm/mol.K×0.0394\ mol×(25+273)\ K/10.0\ L$ $P=0.096\ atm$
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