## Chemistry and Chemical Reactivity (9th Edition)

Number of moles of silane, from ideal gas law: $P.V=n.R.T$ $n=(356\ mmHg/760\ mmHg×1\ atm)×5.20\ L/0.082057\ L.atm/mol.K/(25+273)\ K$ $n=0.0996\ mol$ From stoichiometry: $0.199\ mol$ of $O_2$ From ideal gas law: $P.V=n.R.T$ $V=0.082057\ L.atm/mol.K×0.199\ mol×(25+273)\ K/(425\ mmHg/760\ mmHg×1\ atm)$ $V=8.71\ L$