# Chapter 10 Gases and Their Properties - Study Questions - Page 403b: 16

#### Work Step by Step

Since T and P are the same, $V\propto n$ so, from stoichiometry: $5.2\ L×7/2=18.2\ L$ of $O_2$ required $5.2\ L×6/2=15.6\ L$ of $H_2O$ formed

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