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From the ideal gas law: $P.V=n.R.T$ $n=2.2\ g\div 44.0\ g/mol=0.05\ mol$ $V=0.05\ mol×0.082057\ L.atm/mol.K×(22+273)\ K/(318\ mmHg×1\ atm/760\ mmHg)$ $V=2.92\ L$
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