Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403b: 18


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Work Step by Step

From the ideal gas law: $P.V=n.R.T$ $n=30.0×10^3\ g\div 4.00\ g/mol=7500\ mol$ $V=7500\ mol×0.082057\ L.atm/mol.K×(22+273)\ K/1.20\ atm$ $V=151300\ L$
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