Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 72


$V= 4941.09cm^{3}$

Work Step by Step

1. $10lb = 10\times 453.59237= 4535.9237g$ 2. $V=\frac{m}{p}=\frac{4535.9237}{0.918 g/cm^{3}}=4941.09355cm^{3}$ $V=4941.09355cm^{3} \approx 4941.09cm^{3}$
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