Answer
$$-109^{o}F=-78.3^{o}C$$
Work Step by Step
Since we are given that $-109^{o}F$ is the temperature of dry ice, we can convert to $^{o}C$:
$^{o}C = (-109^{o}F - 32)\div1.8 = -78.3^{o}C$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 51c
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