Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 69b

Answer

3.7L

Work Step by Step

$V=\frac{m}{D}$ $V=\frac{4100g}{1.11g\ ml^{-1}}= 3694mL \approx 3.7L$
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