Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 67


$1.26 g/cm^{3}$

Work Step by Step

$1mL = 1cm^{3}$ $\frac{4.10 \times 10^{3}g} { 3.25L} \times\frac{L}{1000mL} = 1.26g/mL = 1.26g/cm^{3}$
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