Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic - Page 39: 71


The mass of the fuel is $201\times10^{3}g$

Work Step by Step

1. The density equation is $D=\frac{m}{v}$ 2.$Density of Fuel = 0.821 g/cm^{3}$ 3. $V= 245 L = \frac{1000 ml}{1 L} = 245,000 ml$ 4. Rearrange the density equation for mass. $m=VXD$ 5. $m= 245,000 ml \times 0.821 \frac{g}{ml}$ 6. The mass of the fuel is equal to $201,145 g$ or $201\times10^{3}g$
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