Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems - Page 41: 130



Work Step by Step

We know that $V=\frac{m}{\rho}$ We plug in the known values to obtain: $V=\frac{1.10}{2700}=4.074\times 10^{-4}m^3$ We also know that $V=l\times a \times b$ Where $l$,$a$ and $b$ are length, width and thickness The above equation can be rearranged as $l=\frac{V}{a\times b}$ We plug in the known values to obtain: $l=\frac{4.074\times 10^{-4}}{304\times 10^{-3}\times 0.016\times 10^{-3}}=83.76m$
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