Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems - Page 41: 130

$l=83.76m$

We know that $V=\frac{m}{\rho}$ We plug in the known values to obtain: $V=\frac{1.10}{2700}=4.074\times 10^{-4}m^3$ We also know that $V=l\times a \times b$ Where $l$,$a$ and $b$ are length, width and thickness The above equation can be rearranged as $l=\frac{V}{a\times b}$ We plug in the known values to obtain: $l=\frac{4.074\times 10^{-4}}{304\times 10^{-3}\times 0.016\times 10^{-3}}=83.76m$