Answer
The mass of the ice is $198600$ $kg$
Work Step by Step
1. Convert $ft^{3}$ to $dm^{3}$ using conversion factor $1ft^{3} = 28.3168dm^{3}$.
$7655ft^{3} \times 28.3168dm^{3}/ft^{3}= 216765 dm^{3}$
2. Calculate mass of the ice using density and volume. The density of the ice at zere degrees celcius is equal to $0.9162 kg/dm^{3}$.
$m= V\times p = 216765 dm^{3} \times 0.9162 kg/dm^{3} = 198600 kg $
