Answer
The length of $6.02 \times 10^{23}$ hydrogen atoms is $1.276 \times 10^{11}$, while the length of the $6.02 \times 10^{23}$ ping pong ball is $2.408 \times 10^{19}$
Work Step by Step
1. Convert nm to km by using conversion factors and calculate the leght of hydrogen atoms:
$1nm = 1 \times 10 ^{-15} km$
$212 nm = 2.12 \times 10^{-13} km$
$2.12 \times 10^{-13} km \times 6.02 \times 10^{23} = 1.27624 \times 10^{11} km$
2 Convert nm to km by using conversion factors and calculate the leght of ping pong balls:
$1cm = 1 \times 10 ^{-5} km$
$4 cm = 4 \times 10^{-5} km$
$4 \times 10^{-5} km \times 6.02 \times 10^{23} = 2.408 \times 10^{19} km$
