Answer
$0.28 lb/in^{3}$
Work Step by Step
Convert the density of Iron from $g/cm^{3}$ to $lb/in^{3}$ by using the following conversion factors:
$1lb=453.5926g$
$1in^{3}=16.3871cm^{3}$
$p = \frac{7.86 g/cm^{3} \times 16.3871 cm^{3}/in^{3} }{453.5926 g/lb} = 0.284 lb/in^{3}\approx 0.28lb/in^3$
