Answer
Final pressure $P_2=51223.05\text{ torr}$
Work Step by Step
Initial volume $V_1=5.0 ×10^{2} mL=0.5 L$
Initial temperature $T_1=(30+273)K=303K$
Initial pressure $P_1=710 torr$
Final volume $V_2=25 mL=0.025 L$
Final temperature $T_2=(820+273)K=1093K$
Initial pressure $P_2=(T_2P_1V_1)/(T_1V_2)=(1093 × 710×0.5)/(303×0.025)=51223.05 \text{ torr}$
