Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 236: 45


$0.89\text{ moles}$

Work Step by Step

$\frac{n_1}{V_1}=\frac{n_2}{V_2}$ $\frac{0.50\text{ mol}}{11.2\text{ L}}=\frac{n_2}{20. \text{ L}}$ $n_2=0.89\text{ moles}$
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