Answer
$0.89\text{ moles}$
Work Step by Step
$\frac{n_1}{V_1}=\frac{n_2}{V_2}$
$\frac{0.50\text{ mol}}{11.2\text{ L}}=\frac{n_2}{20. \text{ L}}$
$n_2=0.89\text{ moles}$
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 5 - Gases - Exercises - Page 236: 45
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