Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises: 44

Answer

$239\text{ mL}$

Work Step by Step

20.0 C = 293.0 K $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ $\frac{7.00*10^2\text{ mL}}{293.0 \text{ K}}=\frac{V_2}{1.00*10^{2}\text{ K}}$ $V_2=239\text{ mL}$
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