## Chemistry 9th Edition

$239\text{ mL}$
20.0 C = 293.0 K $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ $\frac{7.00*10^2\text{ mL}}{293.0 \text{ K}}=\frac{V_2}{1.00*10^{2}\text{ K}}$ $V_2=239\text{ mL}$