Answer
$239\text{ mL}$
Work Step by Step
20.0 C = 293.0 K
$\frac{V_1}{T_1}=\frac{V_2}{T_2}$
$\frac{7.00*10^2\text{ mL}}{293.0 \text{ K}}=\frac{V_2}{1.00*10^{2}\text{ K}}$
$V_2=239\text{ mL}$
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