Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 236: 54


$0.046\text{ L}$

Work Step by Step

$0.050\text{ mL}*\frac{1.149\text{ g}}{1\text{ mL}}*\frac{1\text{ mol}}{31.9988\text{ grams}}=0.0018\text{ mols}$ $PV=nRT$ $1.0*V=0.0018*0.08206*310$ $V=0.046\text{ L}$
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