## Chemistry 9th Edition

Published by Cengage Learning

# Chapter 5 - Gases - Exercises: 49

#### Answer

$44.8 \text{ grams$H_2$}$ $88.9 \text{ grams$He$}$

#### Work Step by Step

$PV=nRT$ $2.70*200.0=n*0.08206*(24+273)$ $n=22.2\text{ mol}$ $22.2\text{1 mol$H_2$}*\frac{\text{2.01588 grams$H_2$}}{1 \text{ mol$H_2$}}=44.8 \text{ grams$H_2$}$ $22.2\text{1 mol$He$}*\frac{\text{4.00260 grams$He$}}{1 \text{ mol$He$}}=88.9 \text{ grams$He$}$

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