Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 236: 49


$44.8 \text{ grams $H_2$}$ $88.9 \text{ grams $He$}$

Work Step by Step

$PV=nRT$ $2.70*200.0=n*0.08206*(24+273)$ $n=22.2\text{ mol}$ $22.2\text{1 mol $H_2$}*\frac{\text{2.01588 grams $H_2$}}{1 \text{ mol $H_2$}}=44.8 \text{ grams $H_2$}$ $22.2\text{1 mol $He$}*\frac{\text{4.00260 grams $He$}}{1 \text{ mol $He$}}=88.9 \text{ grams $He$}$
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